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Equation Based Solving: Introducing discontinuity in solution at an internal boundary

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Consider a 1d problem consisting of 2 intervals. I am solving a DE for variable 'u'.
If I want that at the junction between the two intervals there should be a discontinuity i.e.

u(l) - u(r) = 1 (for example)

u(l) = value of u at left of junction (lying in interval-1);
u(r) = value of u at right of junction (lying in interval-2);

I have gone through the documentation, videos, blog posts, forum posts but could not find a straight forward answer to this simple problem. It seems like the weak form implementation may help in this but I could not figure out how.

Any help, redirection would help.

0 Replies Last Post 2016年6月29日 GMT-4 16:18
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