Note: This discussion is about an older version of the COMSOL Multiphysics® software. The information provided may be out of date.
Discussion Closed This discussion was created more than 6 months ago and has been closed. To start a new discussion with a link back to this one, click here.
Convective cooling expression
Posted 2012年5月2日 GMT-4 11:15 Heat Transfer & Phase Change, Modeling Tools & Definitions, Parameters, Variables, & Functions Version 4.2a 1 Reply
Please login with a confirmed email address before reporting spam
Hello:
In Heat Transfer module, what is the reference for expression for convective heat transfer coefficient for external natural convection and others, such as Rayleigh #?
COMSOL shows following expression for ht.h_cc
nojac(ht3.kExtFluid_cc2*(flc1hs(1000000000-ht3.Ra_cc2,100000000)*(0.68+0.67*ht3.Ra_cc2^0.25*cos(ht3.phi_tilt)/(1+(0.492*ht3.kExtFluid_cc2/(ht3.muExtFluid_cc2*ht3.CExtFluid_cc2))^0.5625)^0.4444444444444444)+flc1hs(-1000000000+ht3.Ra_cc2,100000000)*(0.825+0.387*ht3.Ra_cc2^(1/6)/(1+(0.492*ht3.kExtFluid_cc2/(ht3.muExtFluid_cc2*ht3.CExtFluid_cc2))^0.5625)^0.2962962962962963)^2)/3)
Thanks
In Heat Transfer module, what is the reference for expression for convective heat transfer coefficient for external natural convection and others, such as Rayleigh #?
COMSOL shows following expression for ht.h_cc
nojac(ht3.kExtFluid_cc2*(flc1hs(1000000000-ht3.Ra_cc2,100000000)*(0.68+0.67*ht3.Ra_cc2^0.25*cos(ht3.phi_tilt)/(1+(0.492*ht3.kExtFluid_cc2/(ht3.muExtFluid_cc2*ht3.CExtFluid_cc2))^0.5625)^0.4444444444444444)+flc1hs(-1000000000+ht3.Ra_cc2,100000000)*(0.825+0.387*ht3.Ra_cc2^(1/6)/(1+(0.492*ht3.kExtFluid_cc2/(ht3.muExtFluid_cc2*ht3.CExtFluid_cc2))^0.5625)^0.2962962962962963)^2)/3)
Thanks
1 Reply Last Post 2012年5月2日 GMT-4 15:28