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Posted:
1 decade ago
2012年5月16日 GMT-4 02:00
Did you try --derived values--integration--surface--with your new cut plane (the 2nd cut plane).
I should give you the integrated velocity value, also based on what i get from your post, only 2nd cut plane should suffice. You may not need to create the first cut plane if you want to integrate over the 2nd cut plane surface.
Good luck.
Did you try --derived values--integration--surface--with your new cut plane (the 2nd cut plane).
I should give you the integrated velocity value, also based on what i get from your post, only 2nd cut plane should suffice. You may not need to create the first cut plane if you want to integrate over the 2nd cut plane surface.
Good luck.
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Posted:
1 decade ago
2012年5月16日 GMT-4 10:34
Hello Mranal,
Thank you for the tip.
I do know the integral function, but I could not separately cut out the 2nd slice.
Even when I performed the 3-points 'cut plane', the slice seemed to cut through the entire geometry passing those three points.
Is there a way to directly specify a small patch with an arbitrary surface area anywhere within the domain?
As you said, I could then just find the flow rate using the integral function in that surface.
Best,
Tae Jin Kim
Hello Mranal,
Thank you for the tip.
I do know the integral function, but I could not separately cut out the 2nd slice.
Even when I performed the 3-points 'cut plane', the slice seemed to cut through the entire geometry passing those three points.
Is there a way to directly specify a small patch with an arbitrary surface area anywhere within the domain?
As you said, I could then just find the flow rate using the integral function in that surface.
Best,
Tae Jin Kim
Ivar KJELBERG
COMSOL Multiphysics(r) fan, retired, former "Senior Expert" at CSEM SA (CH)
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Posted:
1 decade ago
2012年5月16日 GMT-4 10:48
Hi
the cut plane cuts out the full model, if you want to limit the area, you need to multiply your integrand by two bolean operations such as (1<x)*(-1<y)*integrand*(x<2)*(y<3)
but be careful with the average() operator as it considers the full area and not the limited one
--
Good luck
Ivar
Hi
the cut plane cuts out the full model, if you want to limit the area, you need to multiply your integrand by two bolean operations such as (1
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Posted:
1 decade ago
2012年5月16日 GMT-4 14:48
As Ivar suggested, the best way is to use logical expressions.
Other option is using parametric surfaces; for instance if you want to cut a circular planar surface; we can use the following:
data sets >> parameterized surface>> s1 varying 0-2*pi>>s2 varying 0-R
expression x = x1 or any value where yz circular plane is located
y = s2*cos(s1)
z = s2*sin(s1)
that should give you a circular surface (of radius R in yz plane at x = x1) in your geometry which you could use for integration or any other operation. But we need to parameterized the surface which would be difficult for irregular shaped surfaces.
Good luck.
As Ivar suggested, the best way is to use logical expressions.
Other option is using parametric surfaces; for instance if you want to cut a circular planar surface; we can use the following:
data sets >> parameterized surface>> s1 varying 0-2*pi>>s2 varying 0-R
expression x = x1 or any value where yz circular plane is located
y = s2*cos(s1)
z = s2*sin(s1)
that should give you a circular surface (of radius R in yz plane at x = x1) in your geometry which you could use for integration or any other operation. But we need to parameterized the surface which would be difficult for irregular shaped surfaces.
Good luck.
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Posted:
1 decade ago
2012年5月16日 GMT-4 16:51
I forgot to add in last post; as you have asked for a rectangular yz plane; just vary s1 from y1 to y2 and s2 from z1 to z2
expressions > x = x1; y = s1; z = s2 ... that you give you a small rectangular cut plane.
Good luck.
I forgot to add in last post; as you have asked for a rectangular yz plane; just vary s1 from y1 to y2 and s2 from z1 to z2
expressions > x = x1; y = s1; z = s2 ... that you give you a small rectangular cut plane.
Good luck.
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Posted:
1 decade ago
2012年5月16日 GMT-4 17:42
Hello Mranal and Ivar,
I was curious what the parameterized surface stood for but now I know; it's exactly what I needed.
Thank you so much for the help!
Best,
TJ
Hello Mranal and Ivar,
I was curious what the parameterized surface stood for but now I know; it's exactly what I needed.
Thank you so much for the help!
Best,
TJ
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Posted:
1 decade ago
2014年4月15日 GMT-4 09:27
hi
i have a similar problem.
i want to find the average velocity(or flow rate) in a section in the middle of my 3D channel but i do not know how!!! i tried to find the velocity using cut plane, cut line 3D and so on, but non of them was useful. would you mind please help me with my problem.
thank you so much
hamid
hi
i have a similar problem.
i want to find the average velocity(or flow rate) in a section in the middle of my 3D channel but i do not know how!!! i tried to find the velocity using cut plane, cut line 3D and so on, but non of them was useful. would you mind please help me with my problem.
thank you so much
hamid
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Posted:
9 years ago
2015年12月10日 GMT-5 15:50
I forgot to add in last post; as you have asked for a rectangular yz plane; just vary s1 from y1 to y2 and s2 from z1 to z2
expressions > x = x1; y = s1; z = s2 ... that you give you a small rectangular cut plane.
Good luck.
Dear Mranal,
I tried plotting Parameterized Surface as you suggested, but I have got a error (see the attachment). Could you please point out a mistake?
[QUOTE]
I forgot to add in last post; as you have asked for a rectangular yz plane; just vary s1 from y1 to y2 and s2 from z1 to z2
expressions > x = x1; y = s1; z = s2 ... that you give you a small rectangular cut plane.
Good luck.
[/QUOTE]
Dear Mranal,
I tried plotting Parameterized Surface as you suggested, but I have got a error (see the attachment). Could you please point out a mistake?