Note: This discussion is about an older version of the COMSOL Multiphysics® software. The information provided may be out of date.
Discussion Closed This discussion was created more than 6 months ago and has been closed. To start a new discussion with a link back to this one, click here.
Using integration coupling variables
Posted 2013年6月24日 GMT-4 22:12 Version 3.5a 1 Reply
Please login with a confirmed email address before reporting spam
Dear all and Ivar Kjelberg,
I used to integration coupling variable--->Point variables in order to derive integration velocity (u) and I got displacement (dr) in results for the case of 2D. But right now, my direction research is in 2D axisymmetric. Of course, if I used the integral equation similar to the case of 2D, the displacement results will be wrong.
Does anyone can give me suggestion about integration velocity equation in 2D-axisymmetric? I used moving mesh coupled with heat transfer and laminar two-phase flow, phase field.
Thanks so much!!!!
I used to integration coupling variable--->Point variables in order to derive integration velocity (u) and I got displacement (dr) in results for the case of 2D. But right now, my direction research is in 2D axisymmetric. Of course, if I used the integral equation similar to the case of 2D, the displacement results will be wrong.
Does anyone can give me suggestion about integration velocity equation in 2D-axisymmetric? I used moving mesh coupled with heat transfer and laminar two-phase flow, phase field.
Thanks so much!!!!
1 Reply Last Post 2013年6月24日 GMT-4 22:43
Please login with a confirmed email address before reporting spam
Posted:
1 decade ago
Note that dont forget to multiply 2*pi*r with the integration velocity equation. But I'm also not sure this equation can derive to displasement or not.
int(2*pi*r*v) = displacement dr??? I'm still confused that because 2*pi*r*v = m^3/s # displacement.
We should use subdomain varaiable or boundary variable? Maybe we will wait the answer from Mr Ivar Kjelberg is sure.
Thanks alot!!!
int(2*pi*r*v) = displacement dr??? I'm still confused that because 2*pi*r*v = m^3/s # displacement.
We should use subdomain varaiable or boundary variable? Maybe we will wait the answer from Mr Ivar Kjelberg is sure.
Thanks alot!!!