Note: This discussion is about an older version of the COMSOL Multiphysics® software. The information provided may be out of date.
Discussion Closed This discussion was created more than 6 months ago and has been closed. To start a new discussion with a link back to this one, click here.
Joule Losses with Joule Heating module
Posted 2013年11月29日 GMT-5 15:18 Low-Frequency Electromagnetics, Heat Transfer & Phase Change Version 4.3 0 Replies
Please login with a confirmed email address before reporting spam
I need some help.
Currently i'm simulating a ring copper wire (in air), using a 2D axisym with two modules: Magnetic Fields (mf) and Joule Heating (jh).
I defined current in this ring in the mf module to obtain a density of 6e6 A/m^2. Then i used a "heat source" of the Joule heating module originated by the "General source-Electromagnetic heating (mf)".
I was hoping to compute the temperature increase due to the Joule losses, but when I do a 2D plot of the "resistive losses [W/m^3]" and the result is strange. I thought the obvious result it would be:
- "Electrical resistivity of copper [ohm.m]"x"Density current [A/m^2]"^2. In my case 1.6667e-08x(6e6)^2=6e5 [W/m^3]
- but the results shows a resistive losses of 1e5 [W/m^3].
My questions are:
- I am using the right modules to do that?
- Can I define a "heat source" of the Joule module "General source-Electromagnetic heating (mf)" to refer the Joule losses in the copper?
Thanks for your attention,
The best rewards,
João Fernandes
Hello João Fernandes
Your Discussion has gone 30 days without a reply. If you still need help with COMSOL and have an on-subscription license, please visit our Support Center for help.
If you do not hold an on-subscription license, you may find an answer in another Discussion or in the Knowledge Base.