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I have two models, model 1 and model 2. When solving model 2, the initial value of model 2 is the result of model 1. should I set it ?
Posted 2014年3月24日 GMT-4 08:03 Low-Frequency Electromagnetics, Results & Visualization, Studies & Solvers Version 4.3b 0 Replies
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(1) Model 1 and model 2 are same, include: exciting coil, pick-up coil and ferromagnetic pipe. Exciting coil is used to load current, pick-up coil is used to receive inducted voltage. Pipe is nonlinear. when current is in different stages, the B-H curve of pipe is different.
(2) The loaded current is shown in fig.1. When the time is 0-5 ms(denote as t1), the current ascends(I1), when the time is 5ms-50 ms(denote as t2), the current descends(I2).
fig.1
(3) The B-H curve of pipe is different. when the time is t1, the B-H curve ascends (BH1) , when the time is t2, the B-H curve descends (BH2) .
(4) Two models and two solvers. in materials, the B-H curves is different. They are shown in fig.2.
fig. 2
(5) The setting of solver 1 is the fig. 3: (a) is the step1: calculating coil current. (b) is the step2: calculating coil current 2. (c) is the step3: transient. The values of dependent variables are not to be chose.
fig. 3 (a)
fig. 3 (b)
fig. 3 (c)
(6) The setting of solver 2 is the fig. 4: (a) is the step1: calculating coil current. (b) is the step2: calculating coil current 2. (c) is the step3: transient. The values of dependent variables are to be chose in fig.4.(a), (b), (c). I hope the initial values of solver2 is the result of solver1.
fig. 4 (a)
fig. 4 (b)
fig. 4 (c)
(7) Induced voltage curve of solver 1 is shown in fig. 5. It is right. The induced voltage curve of solver 2 is shown in fig. 6(a), the fig. 6(b) is the enlarged view. However, the results are all zero. It is wrong. Why the results are zero?
fig. 5
fig. 6 (a) and (b)
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Hello Xin Wei
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