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Circular rotation

Posted 2010年10月28日 GMT-4 08:36 5 Replies

Nazar
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Hi

I am a new user of COMSOl and have a very basic simple model to simulate, I have imported a spring coil from Autocad and want to apply a circular force in order to rotate it, Can anyone help me with this circular force problem because i am able to apply force in any one direction by defining force in x,y,z direction but i need to define it in circular path but not in a circular path
5 Replies Last Post 2010年10月29日 GMT-4 08:59
Edgar Kaiser
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Posted: 1 decade ago 2010年10月28日 GMT-4 08:45
Muhammad,

there is no thing as a circular force. If you want to apply a torque M you must find how to define the Force vector F according to the vector equation M = F x r. M, F, r are all vectors.

Regards
Edgar
Muhammad, there is no thing as a circular force. If you want to apply a torque M you must find how to define the Force vector F according to the vector equation M = F x r. M, F, r are all vectors. Regards Edgar
Nazar
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Posted: 1 decade ago 2010年10月28日 GMT-4 08:51
Thanx Edgar,

But can you please elaborate your answer. lets say i have a circular plate of radius r and height h and i want to apply twist of an angle Theta, what should i do ?
Thanx Edgar, But can you please elaborate your answer. lets say i have a circular plate of radius r and height h and i want to apply twist of an angle Theta, what should i do ?
Edgar Kaiser
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Posted: 1 decade ago 2010年10月28日 GMT-4 09:41
Muhammad,

you would probably set one face of your disc to the boundary condition fixed and calculate the displacements of the other face according to the twist angle Theta.
Say the axis of your disc points in z direction, then your displacements are:
Rz = 0
Rx and Ry are to be calculated as functions of x, y and Theta for the other face of the disc. You can enter such expressions into the Constraint fields in the prescribed displacement boundary condition.

An example: along the x-axis you have:
Rx = x . sin(Theta)
Ry = x . (1 - cos(Theta))

Now generalize these expressions for the x-y-plane and you are done.

Regards
Edgar
Muhammad, you would probably set one face of your disc to the boundary condition fixed and calculate the displacements of the other face according to the twist angle Theta. Say the axis of your disc points in z direction, then your displacements are: Rz = 0 Rx and Ry are to be calculated as functions of x, y and Theta for the other face of the disc. You can enter such expressions into the Constraint fields in the prescribed displacement boundary condition. An example: along the x-axis you have: Rx = x . sin(Theta) Ry = x . (1 - cos(Theta)) Now generalize these expressions for the x-y-plane and you are done. Regards Edgar
Ivar KJELBERG COMSOL Multiphysics(r) fan, retired, former "Senior Expert" at CSEM SA (CH)
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Posted: 1 decade ago 2010年10月29日 GMT-4 01:22
Hi

as a good example take the moment load in the 3.5a structural application mode documentation

--
Good luck
Ivar
Hi as a good example take the moment load in the 3.5a structural application mode documentation -- Good luck Ivar
Nazar
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Posted: 1 decade ago 2010年10月29日 GMT-4 08:59
thankyou al

The information was really helpful
thankyou al The information was really helpful

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