Discussion Closed This discussion was created more than 6 months ago and has been closed. To start a new discussion with a link back to this one, click here.
Getting capacitance from Impedance/admittance
Posted 2011年3月16日 GMT-4 10:00 Low-Frequency Electromagnetics Version 5.2 6 Replies
Please login with a confirmed email address before reporting spam
Good day!
I am modeling an impedance/capacitance sensor. I have a static model and the results are very promising, now Im trying to expand my model and model a frequency domain study: the voltage applied is a frequency parameter sweep between 1 and 8 MHz. Using the Electric currents interface I can get admittance of the system as a variable but I would also like to know the capacitance of the system.
Since the device is basicaly a microstrip capacitor then I can get the Capacitnace by dividing theimaginary part of admittance by angular frequency.
C = jY/w.
But is there a way to do it automaticaly? There is an example in the library - capacitance in a microstrip(Model ID 966), its exactly what Im trying to do but it is made for 3.5 and when i open it in 4 or 4.1 it seems to work as it should: there are electro statics and magnetic fields physics interfaces and the study is stationary... Solving it brings up an error. Reading the .pdf file for it I found that you can do that by plotting "imag(Y11_emqap)/omega_emqap". However the the variable with imaginary part of admittance doesnt seem to be present in the electric currents interface...
Any help apreciated.
Cheers.
- Fjodor
I am modeling an impedance/capacitance sensor. I have a static model and the results are very promising, now Im trying to expand my model and model a frequency domain study: the voltage applied is a frequency parameter sweep between 1 and 8 MHz. Using the Electric currents interface I can get admittance of the system as a variable but I would also like to know the capacitance of the system.
Since the device is basicaly a microstrip capacitor then I can get the Capacitnace by dividing theimaginary part of admittance by angular frequency.
C = jY/w.
But is there a way to do it automaticaly? There is an example in the library - capacitance in a microstrip(Model ID 966), its exactly what Im trying to do but it is made for 3.5 and when i open it in 4 or 4.1 it seems to work as it should: there are electro statics and magnetic fields physics interfaces and the study is stationary... Solving it brings up an error. Reading the .pdf file for it I found that you can do that by plotting "imag(Y11_emqap)/omega_emqap". However the the variable with imaginary part of admittance doesnt seem to be present in the electric currents interface...
Any help apreciated.
Cheers.
- Fjodor
6 Replies Last Post 2016年10月27日 GMT-4 11:34