Ivar KJELBERG
COMSOL Multiphysics(r) fan, retired, former "Senior Expert" at CSEM SA (CH)
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Posted:
1 decade ago
2013年1月30日 GMT-5 13:10
Hi
the Heavyside functions of 3.5 are now readily available as Definitions - Functions : such as step, or rectangle or ramp ... , all with smoothing
--
Good luck
Ivar
Hi
the Heavyside functions of 3.5 are now readily available as Definitions - Functions : such as step, or rectangle or ramp ... , all with smoothing
--
Good luck
Ivar
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Posted:
1 decade ago
2013年1月31日 GMT-5 12:45
Hello,
I'm using de COMSOL 4.2a version.
Best regards,
Gueiral
Hello,
I'm using de COMSOL 4.2a version.
Best regards,
Gueiral
Ivar KJELBERG
COMSOL Multiphysics(r) fan, retired, former "Senior Expert" at CSEM SA (CH)
Please login with a confirmed email address before reporting spam
Posted:
1 decade ago
2013年2月1日 GMT-5 00:52
Hi
in v4 look under Model - Definitions - Functions, and check the step, rect or ramp functions, these have Heavyside smoothing included
--
Good luck
Ivar
Hi
in v4 look under Model - Definitions - Functions, and check the step, rect or ramp functions, these have Heavyside smoothing included
--
Good luck
Ivar
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Posted:
1 decade ago
2013年2月1日 GMT-5 17:07
Hi
The ramp function worls perfectly fine, but if your lazy like me and u use the Heaviside function often, its easier to use COMSOL's inbuilt Heaviside function
flc1hs(X,scale)
Hi
The ramp function worls perfectly fine, but if your lazy like me and u use the Heaviside function often, its easier to use COMSOL's inbuilt Heaviside function
flc1hs(X,scale)
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Posted:
1 decade ago
2013年2月4日 GMT-5 09:26
Hello,
Tank you Stevie for your answer.
I need to insert in COMSOL a function or a expression like this:
f is a impact force
f = F_max [flch2(t,t_rise )-flch2(t-t_width ,t_fall )]
where
F=max( F )/ S_max ( N / m 2 )
and
S_max=pi*(2.5e-3/2)^2
F : maximum force (2-5N)
and I don't know how? Could you help me?
Best Regards
Nuno
Hello,
Tank you Stevie for your answer.
I need to insert in COMSOL a function or a expression like this:
f is a impact force
f = F_max [flch2(t,t_rise )-flch2(t-t_width ,t_fall )]
where
F=max( F )/ S_max ( N / m 2 )
and
S_max=pi*(2.5e-3/2)^2
F : maximum force (2-5N)
and I don't know how? Could you help me?
Best Regards
Nuno