Note: This discussion is about an older version of the COMSOL Multiphysics® software. The information provided may be out of date.
Discussion Closed This discussion was created more than 6 months ago and has been closed. To start a new discussion with a link back to this one, click here.
Difference in 3D simulation of duct to rotated 2D simulation?!?
Posted 2013年9月3日 GMT-4 06:25 Fluid & Heat, Geometry, Modeling Tools & Definitions, Parameters, Variables, & Functions Version 4.2a 2 Replies
Please login with a confirmed email address before reporting spam
I created a simulation for a circular duct which is heated by a constant heat flux. Does it make a difference to simulate a 3 dimensional geometry or a 2 dimensional geometry (rectangle: radius*length; rotated around axis)? Are there different results?
I have the following problem right now:
I need to verify that my simulation reaches Nusselt number Nu=4.364 (equals a fully developped thermal flow profile) in the outlet of the duct. To calculate Nu first I need to determine the mixed temperature. There are two methods:
1. Integral from axis to wall over the local Temperature divided by radius OR
2. Volume integral over the local Temperature divided by the basis (radius^2*pi)
Due to the fact that the temperature closer to the wall has a greater influence caused by the higher perimeter than the temperature near the axis, method 2 gives a higher mixed temperature.
BUT the Nusselt number of method 2 is always too high. Only method 1 gives the correct answer although it does not weigh the influence of each local temperature considering the location.
PS: Both methods were tested with a fictional temparture profile of T(r)=r^2. Method 2 is 99.9999% of the analytical solution. Method 1 only about 67%.
I simply don't get it, that a tested method to determine the mixed temperature leads to a wrong result...
Hello Fabian Holz
Your Discussion has gone 30 days without a reply. If you still need help with COMSOL and have an on-subscription license, please visit our Support Center for help.
If you do not hold an on-subscription license, you may find an answer in another Discussion or in the Knowledge Base.
Please login with a confirmed email address before reporting spam
Could you mind telling me in your case,
how to impose a constant heat flux BC?
i am doing the some job as you to find the Nusselt number close to 4.364, but when i impose a heat flux BC with
genearl inward heat flux equals to a constant value (150 W/^2), i find the heat flux varies from one end of the circurlar tube to the other end, and only average heat flux over the wall is constant (150 W/m^2).
SO, Could you help me with this problem?
Thanks a lot!
Please login with a confirmed email address before reporting spam