Note: This discussion is about an older version of the COMSOL Multiphysics® software. The information provided may be out of date.
Discussion Closed This discussion was created more than 6 months ago and has been closed. To start a new discussion with a link back to this one, click here.
Asymmetrical & one-directional torque on rotating particle about center point
Posted 2014年6月8日 GMT-4 18:28 Low-Frequency Electromagnetics, Geometry, Results & Visualization, Studies & Solvers Version 4.2 0 Replies
Please login with a confirmed email address before reporting spam
In my case, I am calculating the torque on a 2D triangular particle suspended in a liquid medium over a gap between biased electrode digits (on the x-y plane running parallel to the y axis) as a function of the rotation of the particle in the x-z plane using DC model (please see the attached .gif). The particle is centered over the biased gap, and lying parallel to the electrode surface is defined as having 0 rotation. As the particle is rotated about its axis parallel to the electrode edges ( the y-axis), the torque on the particle about this axis should be symmetrical about its original position (flat), but in opposite directions (opposite signs).
However, Comsol outputs a torque that is asymmetrical about zero rotation and is always positive (torque is only in one direction). I believe these are artifacts of the modeling because the torque profile did not change when I switched the bias on the electrode digits. In addition, I tested the symmetry using a flat square particle with obvious geometrical symmetry, and obtained similarly asymmetrical results.
I have been using custom meshing with small elements and low growth rate, so I don't believe that to be the issue, but any help is appreciated.
Thank you in advance,
Donna
Attachments:
Hello Donna Deng
Your Discussion has gone 30 days without a reply. If you still need help with COMSOL and have an on-subscription license, please visit our Support Center for help.
If you do not hold an on-subscription license, you may find an answer in another Discussion or in the Knowledge Base.