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Curvature using divergence of surface normal

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Hello,

I want to calculate the curvature of a 3D surface in a 2D axisymmetric model. The variable 'curv' only gives the curvature of the curve in the 2D axisymmetric plane, not the full 3D curvature. For instance, if I were to draw a straight, sloped line in the axisymmetric plane (creating a cone), the variable 'curv' would be equal to zero.

The curvature is proportional to div(n) or, equivalently, dtang(n) where n is the unit normal to the surface. I tried to calculate these by doing d(nr*r,r)/r+d(nz,z) or dtang(nr*r)/r+dtang(nz,z) but it won't output anything. It isn't giving me an error, it just creates a blank plot when I try to plot the curvature vs. arc length of the curve.

Does anyone know what I'm doing wrong here?

Thanks

1 Reply Last Post 2015年6月18日 GMT-4 10:01
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Hello TGA

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Posted: 9 years ago 2015年6月18日 GMT-4 10:01
Were you ever able to find a solution to this?

Regards,

Brandon
Were you ever able to find a solution to this? Regards, Brandon

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