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Cell constant of an irregular shaped object

Posted 2014年1月7日 GMT-5 10:35 Low-Frequency Electromagnetics 2 Replies

Xiaofei Guan
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Dear all,

Is there a way to calculate the cell constant of an irregular shaped object using COMSOL?

Thanks,
Daniel
2 Replies Last Post 2014年1月9日 GMT-5 01:13
Edgar J. Kaiser Certified Consultant
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Posted: 1 decade ago 2014年1月7日 GMT-5 11:51

What is a cell constant in your case? The term is sometimes used in the context of electrolytic cells, but you are just talking about an irregular shaped object?

Cheers
Edgar

--
Edgar J. Kaiser
emPhys Physical Technology
www.emphys.com
What is a cell constant in your case? The term is sometimes used in the context of electrolytic cells, but you are just talking about an irregular shaped object? Cheers Edgar -- Edgar J. Kaiser emPhys Physical Technology http://www.emphys.com
Xiaofei Guan
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Posted: 1 decade ago 2014年1月9日 GMT-5 01:13
Hi Edgar,

Thank you for your reply.

In the electrolysis cell I am studying with, part of the electrolyte has an irregular shape. I already figured out how to calculate the cell constant using the Electric Current mode in COMSOL. The 'effective' cell constant can be calculated by dividing the electric potential drop by the total current and the resistivity of the electrolyte.

Thanks!
Daniel


What is a cell constant in your case? The term is sometimes used in the context of electrolytic cells, but you are just talking about an irregular shaped object?

Cheers
Edgar

--
Edgar J. Kaiser
emPhys Physical Technology
www.emphys.com


Hi Edgar, Thank you for your reply. In the electrolysis cell I am studying with, part of the electrolyte has an irregular shape. I already figured out how to calculate the cell constant using the Electric Current mode in COMSOL. The 'effective' cell constant can be calculated by dividing the electric potential drop by the total current and the resistivity of the electrolyte. Thanks! Daniel [QUOTE] What is a cell constant in your case? The term is sometimes used in the context of electrolytic cells, but you are just talking about an irregular shaped object? Cheers Edgar -- Edgar J. Kaiser emPhys Physical Technology http://www.emphys.com [/QUOTE]

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