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Posted:
10 years ago
2015年2月11日 GMT-5 05:14
1. What is the material, i.e. its thermal conductivity or thermal diffusivity?
2. What is the heat transfer coefficient between the block and its surroundings? It is not guaranteed that the outer edges of the block remain at 25 °C all the time, unless you force it somehow.
Knowing these parameters the simulation is most straightforward.
br
Lasse
1. What is the material, i.e. its thermal conductivity or thermal diffusivity?
2. What is the heat transfer coefficient between the block and its surroundings? It is not guaranteed that the outer edges of the block remain at 25 °C all the time, unless you force it somehow.
Knowing these parameters the simulation is most straightforward.
br
Lasse
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Posted:
10 years ago
2015年2月11日 GMT-5 07:57
Thank you for the prompt reply.
For the parameter I have:
k = 42 w/m.k
C = 750 j/kg.k
about the environment around the block, how can i introduce or force it to interact with sample at a certain temperature?
there are two surroundings
1- on top of the surface (where the heat release on a) there is water which moving really fast and doesn't heat up itself and just take the heat away from the sample
2- at the bottom of sample there is air which can be heated up
Thank you for the prompt reply.
For the parameter I have:
k = 42 w/m.k
C = 750 j/kg.k
about the environment around the block, how can i introduce or force it to interact with sample at a certain temperature?
there are two surroundings
1- on top of the surface (where the heat release on a) there is water which moving really fast and doesn't heat up itself and just take the heat away from the sample
2- at the bottom of sample there is air which can be heated up
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Posted:
10 years ago
2015年2月11日 GMT-5 08:25
Heat transfer from the solid to the surrounding fluid is taken into account through Newton's cooling law:
q = h·(Text - T)
where Text is the fluid temperature and T is the solid temperature; h is the heat transfer coefficient which depends on materials. For steel-air boundary it is 5-10 W/(m²·K) and for steel-water boundary 300-400 W/(m²·K). Exact values are impossible to give as they depend on the rate of convection, fouling, etc. But I do not think this value plays an important part, because your solid body is very close to 25 °C at all times, hence hardly no heat transfer takes place.
In Comsol this BC is under Heat Flux --> Convective Heat Flux.
Your plate reaches constant temperature of 25 °C in less than 0.5 ms (see attached image).
br
Lasse
Heat transfer from the solid to the surrounding fluid is taken into account through Newton's cooling law:
q = h·(Text - T)
where Text is the fluid temperature and T is the solid temperature; h is the heat transfer coefficient which depends on materials. For steel-air boundary it is 5-10 W/(m²·K) and for steel-water boundary 300-400 W/(m²·K). Exact values are impossible to give as they depend on the rate of convection, fouling, etc. But I do not think this value plays an important part, because your solid body is very close to 25 °C at all times, hence hardly no heat transfer takes place.
In Comsol this BC is under Heat Flux --> Convective Heat Flux.
Your plate reaches constant temperature of 25 °C in less than 0.5 ms (see attached image).
br
Lasse
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Posted:
10 years ago
2015年2月11日 GMT-5 09:08
Perfect, thanks for calculation.
is it possible to share the simulation file. I'm interested to see how you define the environment's temperature to be constant at 25 degree.
Perfect, thanks for calculation.
is it possible to share the simulation file. I'm interested to see how you define the environment's temperature to be constant at 25 degree.
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Posted:
10 years ago
2015年2月11日 GMT-5 09:33
Hi
I removed everything else but geometry and physics in order to keep file size small. Meshing would bring about a much bigger file.
br
Lasse
Hi
I removed everything else but geometry and physics in order to keep file size small. Meshing would bring about a much bigger file.
br
Lasse