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Note: This discussion is about an older version of the COMSOL Multiphysics® software. The information provided may be out of date.

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Photocurrent calculation in RF module

Posted 2013年7月17日 GMT-4 23:18 RF & Microwave Engineering, Modeling Tools & Definitions, Parameters, Variables, & Functions Version 4.3a 4 Replies

Evgeniy Panchenko
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Greetings

I have a solar cell (silicon brick) with metallic rods on the top surface. This is well known structure to enhance the solar cell responsivity with plasmonic effects.
So I want to calculate a photocurrent that can be generated by my structure. To do this I need to know the optical generation rate in the silicon brick. Usually the following formula is used: ecee.colorado.edu/~bart/book/book/chapter4/gif/eq4_7_4.gif . But how can I take in account the impact of plasmonic structure on the top surface? Maybe I should calculate the energy flux (z component of Poynting vector) through the top surface of silicon brick and use it as an input optical power? But in this case how could I know the absorption coefficient of silicon due to a surface plasmon wavelength is shorter than excitation wavelength?

Thank you.
4 Replies Last Post 2017年1月9日 GMT-5 19:10
Evgeniy Panchenko
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Posted: 1 decade ago 2013年7月18日 GMT-4 19:53
I have found the answer on my question. If someone interested read here www.lumerical.com/solutions/innovation/optoelectronic_modeling_photosensitive_devices.html
I have found the answer on my question. If someone interested read here http://www.lumerical.com/solutions/innovation/optoelectronic_modeling_photosensitive_devices.html
Evgeniy Panchenko
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Posted: 1 decade ago 2013年7月19日 GMT-4 01:19
One thing I didn't understand is how they assume that the optical power absorbed per unit volume is equal to www.lumerical.com/resources/images/formula2.jpg . According to Poynting theorem there should be also a magnetic field component and component representing the ohmic losses or power generated by some source. Since we have no power sources or ohmic losses inside the silicon brick I agree that this component is equal to zero. But what about component with magnetic field?
One thing I didn't understand is how they assume that the optical power absorbed per unit volume is equal to http://www.lumerical.com/resources/images/formula2.jpg . According to Poynting theorem there should be also a magnetic field component and component representing the ohmic losses or power generated by some source. Since we have no power sources or ohmic losses inside the silicon brick I agree that this component is equal to zero. But what about component with magnetic field?
M.H.Elshorbagy
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Posted: 9 years ago 2015年12月28日 GMT-5 22:02
I have A question how can I calculate the absorption vs wavelength in the active layer of the following structure
PML/back contact / Active layer / top contact /Air /PML

illuminated by scattered field formulation Ex=E0*exp(-j*kx*x) moving along z direction

is the following formula correct

Abs=0.5*sig*intop1(-relpoav)
where sig=2*pi*freq*im(eps)Si
and relpoav=nx*emw.relpoavx+ny*emw.relpoavy+nz*emw.relpoavz

and intop1 is the volume integration over the active layer volume

I have A question how can I calculate the absorption vs wavelength in the active layer of the following structure PML/back contact / Active layer / top contact /Air /PML illuminated by scattered field formulation Ex=E0*exp(-j*kx*x) moving along z direction is the following formula correct Abs=0.5*sig*intop1(-relpoav) where sig=2*pi*freq*im(eps)Si and relpoav=nx*emw.relpoavx+ny*emw.relpoavy+nz*emw.relpoavz and intop1 is the volume integration over the active layer volume
Riyasat Ohib
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Posted: 8 years ago 2017年1月9日 GMT-5 19:10
Hello, I saw that you found the solution. I am new to Comsol and am learning to model Solar cells. So far, I have failed to find a way to calculate photo-current. It would be of Immense help if you could please share the .mph file.
Thanks a lot.
Hello, I saw that you found the solution. I am new to Comsol and am learning to model Solar cells. So far, I have failed to find a way to calculate photo-current. It would be of Immense help if you could please share the .mph file. Thanks a lot.

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